Answer
$\dfrac{4}{3}$
Work Step by Step
The general formula to find the sum of infinite Geometric series is given as:
$ S_{n}=\dfrac{a_1}{(1-r)}$
and $ r=\dfrac{a_2}{a_1}=\dfrac{1/4}{1}=\dfrac{1}{4}$
Now, $ S_{n}=\dfrac{a_1}{(1-r)}=\dfrac{1}{1-\dfrac{1}{4}}$
Our answer is: $ S_{n}=\dfrac{1}{3/4}=\dfrac{4}{3}$