Answer
$177148$
Work Step by Step
The general formula to find the nth partial sum of a Geometric sequence is given as: $ S_{n}=\dfrac{a(1-r^n)}{(1-r)}$
$ r=\dfrac{a_2}{a_1}=\dfrac{-12}{4}=-3$ and $ n=11$
Now, $ S_{11}=\dfrac{4(1-(-3)^{11})}{(1-(-3))}=4 \times \dfrac{177148}{4}$
Our answer is: $ S_{11}=177148$
