Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Test - Page 306: 31

Answer

The domain of the function $f\left( x \right)$ is $\underline{\left( -\infty ,-5 \right)\cup \left( -5,1 \right)\cup \left( 1,\infty \right)}$.

Work Step by Step

The domain is the set of values of $x$ for which the function $f(x)$ can be defined. Since the denominator for a fraction can’t be 0, therefore the function cannot be defined for $x=1$ and $x=-5$. Clearly, there is no other restriction on $f\left( x \right)$, which means that the function can be defined for all the real values except $x=1$ and $x=-5$. So, the domain of the function is $\left( -\infty ,-5 \right)\cup \left( -5,1 \right)\cup \left( 1,\infty \right)$.
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