Answer
The value of $f\left( x-1 \right)$ with the functions $f\left( x \right)={{x}^{2}}-x-4$ and $g\left( x \right)=2x-6$ is ${{x}^{2}}-3x-2$
Work Step by Step
To calculate the value of $f\left( x-1 \right)$, substitute $x-1$ in place of $x$.
$x\to x-1$
Now, substitute $x-1$ in place of $x$ in the function $f\left( x \right)$ and get
$\begin{align}
& f\left( x-1 \right)={{\left( x-1 \right)}^{2}}-\left( x-1 \right)-4 \\
& ={{x}^{2}}-2x+1-x+1-4 \\
& ={{x}^{2}}-3x-2
\end{align}$
Therefore,
$f\left( x-1 \right)={{x}^{2}}-3x-2$.
Hence, the value of $f\left( x-1 \right)$ with the functions $f\left( x \right)={{x}^{2}}-x-4$ and $g\left( x \right)=2x-6$ is ${{x}^{2}}-3x-2.$
