Answer
$f(x)=\sqrt[3] x$ and $g(x)=x^2-9$
(Other solutions are possible.)
Work Step by Step
One possible solution is:
$f(x)=\sqrt[3] x$ and $g(x)=x^2-9$, such that $h(x)=(f\circ g)(x)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 1 - Section 1.7 - Combinations of Functions; Composite Functions - Exercise Set - Page 259: 77
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