Answer
a. $ 5-x$
b. $(-\infty,1]$
Work Step by Step
Given $f(x)=x^2+4$ and $g(x)=\sqrt {1-x}, x\leq1$, we have:
a. $(f\circ g)(x)=(\sqrt {1-x})^2+4=5-x$
b. The domain of the above function can be found as $\{x|x\leq1\}$ or $(-\infty,1]$