Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 380: 117

Answer

$-\frac{5\pi}{3}, -\frac{11\pi}{3}$, $\frac{\pi}{3}, \frac{7\pi}{3}, \frac{13\pi}{3}$

Work Step by Step

Answer may vary. Step 1. We can identify the given point is in quadrant I with an angle $\frac{\pi}{3}$ from the $+x$-axis. Step 2. We can find two negative equivalent angles as $-\frac{5\pi}{3}, -\frac{11\pi}{3}$ Step 3. We can find three positive equivalent angles as $\frac{\pi}{3}, \frac{7\pi}{3}, \frac{13\pi}{3}$
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