Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 380: 109

Answer

$-\frac{1}{2}$

Work Step by Step

$(f\cdot g)(\frac{3\pi}{4})=\sin{\frac{3\pi}{4}}\cdot\cos{\frac{3\pi}{4}}=\frac{\sqrt2}{2}\cdot-\frac{\sqrt2}{2}=-\frac{1}{2}$
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