Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 380: 110

Answer

$\dfrac{\sqrt3}{4}$

Work Step by Step

RECALL: $(f\cdot g)(x)=f(x)\cdot g(x)$ Use the rule above to obtain: $(f\cdot g)\left(\dfrac{4\pi}{3}\right)=\sin{\left(\dfrac{4\pi}{3}\right)} \cdot \cos{\left(\dfrac{4\pi}{3}\right)}=-\dfrac{\sqrt3}{2} \cdot \left(-\dfrac{1}{2}\right)=\dfrac{\sqrt3}{4}$
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