Answer
$\dfrac{\sqrt3-1}{2}$
Work Step by Step
RECALL:
$(f-g)(x)=f(x)-g(x)$
Use the rule above to obtain:
$(f-g)(60^\circ)=\sin{60^\circ}-\cos{60^\circ}=\dfrac{\sqrt3}{2}-\dfrac{1}{2}=\dfrac{\sqrt3-1}{2}$
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