Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 54

Answer

$\frac{ln1.7+ln0.3}{2ln1.7-ln0.3}\approx-0.297$

Work Step by Step

Take logarithm on both sides to get $(1+x)ln0.3=(2x-1)ln1.7 \longrightarrow (2ln1.7-ln0.3)x=ln1.7+ln0.3 \longrightarrow x=\frac{ln1.7+ln0.3}{2ln1.7-ln0.3}\approx-0.297$
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