Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 10

$x=0$

RECALL: $\log_a{b}=\log_a{c} \longrightarrow b=c$ Hence, $\log_5{(2x+3)}=\log_5{3}\longrightarrow 2x+3=3$. Solve the equation above to obtain \begin{align*} 2x+3-3&=3-3\\ 2x&=0\\ \frac{2x}{2}&=\frac{0}{2}\\ x&=0 \end{align*}