Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 19

Answer

$\frac{21}{8}=2.625$

Work Step by Step

Step 1. Rewrite the equation as $log(2x+1)=log10+log(x-2)$ Step 2. Thus $2x+1=10(x-2)\longrightarrow 2x+1=10x-20\longrightarrow 8x=21\longrightarrow x=\frac{21}{8}$. Step 3. Check answers, $x=\frac{21}{8}=2.625$ fits the original equation.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions