Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 44

Answer

$x=\dfrac{\ln{14}}{\ln{3}} \approx 2.402$

Work Step by Step

Take the $\log_3$ of both sides: $\log_3{(3^x)}=\log_3{14}\\x=\log_3{14}$ We know that $\log_a {b}=\dfrac{\log_c {b}}{\log_c {a}}$ (Change of Base formula). Use a calculator and the change-of-base rule above to obtain $x=\log_3{14}=\dfrac{\ln{14}}{\ln{3}}\approx2.402$
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