Answer
$a_n=4n-6.$ $a_{51}=198.$
Work Step by Step
We know that the $n^{th}$ term $a_n$ of an arithmetic sequence is given by the formula
$a_n=a_1+(n-1)d$
where $d$=common difference and $a_1$= the first term
Hence, here we have
$a_n=-2+(n-1)4\\a_n=-2+4n-4\\a_n=4n-6.$
Therefore
$a_{51}=4\cdot51-6\\a_{51}=204-6\\a_{51}=198.$