Answer
$89964$
Work Step by Step
I know that $\sum_{k=1}^{n} (k^3)=\left[\frac{n(n+1)}{2}\right]^2.$
Hence $\sum_{k=4}^{24} (k^3)=\sum_{k=1}^{24} (k^3)-\sum_{k=1}^{3} (k^3)=\left[\frac{24(24+1)}{2}\right]^2-\left[\frac{3(3+1)}{2}\right]^2=90000-36=89964$