Answer
$955$
Work Step by Step
I know that $\sum_{k=1}^{n} (k^2)=\frac{n(n+1)(2n+1)}{6}.$
Hence $\sum_{k=0}^{14} (k^2-4)=-4+\sum_{k=1}^{14} (k^2-4)=-4+\sum_{k=1}^{14} (k^2)-\sum_{k=1}^{14} (4)=-4+\frac{14(14+1)(28+1)}{6}-14(4)=-4+1015-56=955$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 808: 76
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
