Answer
$1110$
Work Step by Step
I know that $\sum_{k=1}^{n} (k)=\frac{n(n+1)}{2}.$
Hence $\sum_{k=1}^{20} (5k+3)=\sum_{k=1}^{20} (5k)+\sum_{k=1}^{20} (3)=5\sum_{k=1}^{20} (k)+20(3)=5\frac{20(20+1)}{2}+60=1050+60=1110$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 808: 73
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