Answer
$871$
Work Step by Step
I know that $\sum_{k=1}^{n} (k)=\frac{n(n+1)}{2}.$
Hence $\sum_{k=1}^{26} (3k-7)=\sum_{k=1}^{26} (3k)+\sum_{k=1}^{26} (-7)=3\sum_{k=1}^{26} (k)+26(-7)=3\frac{26(26+1)}{2}-182=3(351)-182=871$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.1 Sequences - 12.1 Assess Your Understanding - Page 808: 74
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