Answer
$\begin{matrix}
&-- &-- &--&--& \\
-3) &2&0&-5&1& & \\ \end{matrix}$
Work Step by Step
The given expression is
$(2x^3-5x+1)\div (x+3)$
Rewrite the dividend in descending powers of $x$.
$(2x^3+0x^2-5x+1)\div (x+3)$
The divisor is $x+3$.
Use $-3$ to the left of the division symbol, and the numerical coefficients of the dividend on the right side .
Hence, the first step is
$\begin{matrix}
&-- &-- &--&--& \\
-3) &2&0&-5&1& & \\ \end{matrix}$
