Answer
The walking speed of dinosaur to the nearest tenth in radical form is \[13.9\] feet per second.
Work Step by Step
The walking speed of dinosaur is given by \[4\sqrt{2x}\] feet per seconds.
Now, in this case the length of leg of dinosaur is 6 feet.
So, put \[x=6\] to calculate the speed of dinosaur:
\[\begin{align}
& \text{speed}=4\sqrt{2\times 6} \\
& =4\sqrt{\overline{2\times 2}\times 3} \\
& =4\times 2\sqrt{3} \\
& =8\sqrt{3}
\end{align}\]
Convert speed to the nearest tenth:
\[\begin{align}
& \text{speed}=8\sqrt{3} \\
& =8\times 1.732 \\
& =13.856 \\
& \approx 13.9
\end{align}\]
Hence, the walking speed of dinosaur to the nearest tenth in radical form is \[13.9\] feet per second.
