Answer
$\dfrac{35}{6}$
Work Step by Step
Convert each factor to an improper fraction to find:
$=\dfrac{3(3)+1}{3} \cdot \dfrac{4(1)+3}{4}
\\=\dfrac{10}{3} \cdot \dfrac{7}{4}$
Factor each numerator and denominator, when needed, and then cancel common factors to find:
$\\\require{cancel}=\dfrac{2(5)}{3} \cdot \dfrac{7}{2(2)}
\\=\dfrac{\cancel{2}(5)}{3} \cdot \dfrac{7}{\cancel{2}(2)}
\\=\dfrac{5}{3} \cdot \dfrac{7}{2}$
Multiply the numerators together and the denominators together to find:
$=\dfrac{5(7)}{3(2)}
\\=\dfrac{35}{6}$
