Answer
$\dfrac{\sqrt6}{3}$
Work Step by Step
Rationalize the denominator by multiplying $3$ to both the numerator and the denominator within the radical sign to obtain:
$=\sqrt{\dfrac{2}{3} \cdot \dfrac{3}{3}}
\\=\sqrt{\dfrac{6}{9}}
\\=\sqrt{\dfrac{6}{3^2}}
\\=\dfrac{\sqrt6}{3}$
