University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.5 - Lines and Planes in Space - Exercises - Page 631: 56

Answer

$(-4,-2,-5)$

Work Step by Step

The parametric equations are: $x=-1+3t; y=-2; z=5t$ We have the equation of aplane: $2x-3z=7$ Now, we plug in all of the parametric equations into the above equation of a plane: $t=-1$ Thus, our parametric equations become: $x=-1+3(-1)=-4; y=-2; z=5(-1)=-5$ Hence, the line will meet at the point: $(-4,-2,-5)$
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