Answer
$x+6y+z=16$
Work Step by Step
The normal to the plane is $n=\lt -2,-12,-2 \gt$
We know that the standard equation of a plane passing through the point $(x_0,y_0,z_0)$ is written as: $a(x-x_0)+b(y-y_0)+c(z-z_0)=0$
Then for point $(1,2,3)$, we have
$-2(x-1)-12(y-1)-2(z-3)=0$
or, $-2x-12y-2z=-32$
or, $x+6y+z=16$
