Chapter 11 - Section 11.5 - Lines and Planes in Space - Exercises - Page 631: 34

$3$

The formula to calculate the distance for two vectors is given by: $d=\dfrac{|u \times v|}{|v|}$ Thus, we have $u \times v=\lt -13,16,5\gt $ and $|u \times v|=\sqrt{(-13)^2+(16)^2+(5)^2}=15 \sqrt 2$ Now, $d=\dfrac{|u \times v|}{|v|}=\dfrac{15 \sqrt 2}{5 \sqrt 2}=3$