University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.5 - Lines and Planes in Space - Exercises - Page 631: 50

Answer

$0.96$ rad

Work Step by Step

The formula to calculate the angle between two planes is: $ \theta = \cos ^{-1} (\dfrac{p \cdot q}{|p||q|})$ Here, $p=\lt 1,1,1 \gt$ and $q=\lt 0,0,1 \gt$ $|p|=\sqrt{1^2+1^2+1^2}= \sqrt 3$ and $|q|=\sqrt{0^2+0^2+0^2}=1$ Thus, $ \theta = \cos ^{-1} (\dfrac{p \cdot q}{|p||q|})=\cos ^{-1} (\dfrac{1}{ \sqrt 3})$ or, $ \theta =0.96$
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