Answer
$3(\dfrac{2}{3}i+\dfrac{1}{3}k-\dfrac{2}{3}k)$
Work Step by Step
Here, $v=2i+j-2k$
and $|v|=\sqrt{2^2+1^2+(-2)^2}=\sqrt 9 =3$
The unit vector $\hat{\textbf{v}}$ can be calculated as: $\hat{\textbf{v}}=\dfrac{v}{|v|}$
Now, $\hat{\textbf{v}}=\dfrac{2i+j-2k}{3}$
Thus, $v=|v|\hat{\textbf{v}}=3(\dfrac{2}{3}i+\dfrac{1}{3}k-\dfrac{2}{3}k)$
