Answer
$\lt \dfrac{-1}{2},\dfrac{-\sqrt 3}{2} \gt$
Work Step by Step
Use formula $v=\lt |v| \cos \theta, |v| \sin \theta \gt$
Here, $|v|=1$ and $\theta=\dfrac{2\pi}{3}$
Thus,
$v=\lt (1) \cos (\dfrac{2\pi}{3}), (1) \cos (\dfrac{2\pi}{3}) \gt=\lt \dfrac{-1}{2},\dfrac{-\sqrt 3}{2} \gt$
