University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.2 - Vectors - Exercises - Page 608: 12

Answer

$<0,0>$

Work Step by Step

Here, we have $A=\lt 1,-1 \gt, B=\lt 2,0 \gt, C=\lt -1, 3 \gt, D=\lt -2,2 \gt$ $\overrightarrow{AB}+\overrightarrow{CD}=\lt 1,-1 \gt \lt 2,0 \gt+\lt -1, 3 \gt \lt -2,2 \gt$ or, $\overrightarrow{AB}+\overrightarrow{CD}=\lt 1,1 \gt +\lt -1,-1 \gt=\lt 1-1, 1-1 \gt =<0,0>$
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