Answer
$\lt \dfrac{-1}{ \sqrt 2},\dfrac{1}{\sqrt 2} \gt$
Work Step by Step
The coordinates of a point P on the circle with radius $r$ are: $(r \cos \theta, r \sin \theta)$
Therefore, $\lt 1*\cos (135^{\circ}), 1*\sin (135^{\circ}) \gt=\lt \dfrac{-1}{ \sqrt 2},\dfrac{1}{\sqrt 2} \gt$
