Answer
$10x-13$
Work Step by Step
The linearization of $ f(x)$ at $ x=a $ is
$ L(x)=f(a)+f'(a)(x-a)$
Knowing that $ f(x)=x^{3}-2x+3$, $ f'(x)=3x^{2}-2$ and $ a=2$, we have:
$ L(x)=(2^{3}-2\times2+3)+(3\times2^{2}-2)(x-2)$
$=7+10x-20=10x-13$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.9 - Linearization and Differentials - Exercises 3.9 - Page 174: 1
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
