Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 177: 27

Answer

$y'=8x^3sin(2x^2)cos(2x^2)+2xsin^2(2x^2)$

Work Step by Step

Take the derivative of the equation using Power Rule, Product Rule, Trigonometric derivative, and Chain Rule: $y'=x^2\times2sin(2x^2)\times cos(2x^2)\times4x+2xsin^2(2x^2)$ $=8x^3sin(2x^2)cos(2x^2)+2xsin^2(2x^2)$
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