Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 177: 18

Answer

$r'=\frac{-θsinθ}{(cosθ)^{1/2}}+2(cosθ)^{1/2}$

Work Step by Step

Rewrite the equation: $r=2θ(cosθ)^{1/2}$ Take the derivative of the equation using Trigonometric derivatives, Product Rule, and Chain Rule: $r'=2θ\times\frac{1}{2}(cosθ)^{-1/2}\times-sinθ+2(cosθ)^{1/2}$ $=\frac{-θsinθ}{(cosθ)^{1/2}}+2(cosθ)^{1/2}$
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