Answer
$y'=cos((x)^{1/2})+\frac{sin((x)^{1/2})}{x^{1/2}}$
Work Step by Step
Rewrite the equation: $y=2(x)^{1/2}sin((x)^{1/2})$
Take the derivative of the equation using Trigonometric derivative, Power Rule, and Chain Rule:
$y'=2(x)^{1/2}\times cos((x)^{1/2})\times\frac{1}{2}x^{-1/2}+2\times\frac{1}{2}x^{-1/2}\times sin((x)^{1/2})$
$=cos((x)^{1/2})+\frac{sin((x)^{1/2})}{x^{1/2}}$