Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 1 - Section 1.4 - Linear Regression - Exercises - Page 102: 11

Answer

$y=0.7x+0.85$

Work Step by Step

Regression line $y=mx+b,$ where $m$ and $b$ are computed as follows: $m=\displaystyle \frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^{2})-(\sum x)^{2}}\qquad b=\frac{\sum y-m(\sum x)}{n}$ $n=$ number of data points. The quantities $m$ and $b$ are called the regression coefficients. ----- Build a table \begin{array}{|cc|c|c|c|cc|} \hline & x & y & xy & xx \\ \hline & 0 & -1 & 0 & 0 \\ & 1 & 3 & 3 & 1 \\ & 3 & 6 & 18 & 9 \\ & 4 & 1 & 4 & 16 \\\hline \Sigma & {\bf 8} & {\bf 9} & {\bf 25} & {\bf 26} \\\hline points & 4 & & 100 & 104 \\\hline \end{array} $m=\displaystyle \frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^{2})-(\sum x)^{2}}=\frac{100-(8)(9)}{104-(8)^{2}}=\frac{28}{40}=0.7$ $b=\displaystyle \frac{\sum y-m(\sum x)}{n}=\frac{9-0.7(8)}{4}=0.85$ $y=0.7x+0.85$
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