Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.5 - Solving Polynomial Equations - Exercises - Page 30: 26

Answer

$-1\pm \sqrt 10$

Work Step by Step

$x+1=\frac{1}{x-2}$ $(x-2)(x+4)=1$ $x^{2}+2x-9=0$ $x=\frac{-2\pm \sqrt (2^{2}-4(1)(-9))}{2}=\frac{-2\pm \sqrt 40}{2}=\frac{-2\pm 2\sqrt 10}{2}=-1\pm \sqrt 10$
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