Answer
$-1\pm \sqrt 10$
Work Step by Step
$x+1=\frac{1}{x-2}$
$(x-2)(x+4)=1$
$x^{2}+2x-9=0$
$x=\frac{-2\pm \sqrt (2^{2}-4(1)(-9))}{2}=\frac{-2\pm \sqrt 40}{2}=\frac{-2\pm 2\sqrt 10}{2}=-1\pm \sqrt 10$
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