Answer
no real solutions
Work Step by Step
Quadratic formula, a=1, b=1, c=1
$x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$
$x=\displaystyle \frac{-1\pm\sqrt{1^{2}-4(1)(1)}}{2(1)}$
$x=\displaystyle \frac{-1\pm\sqrt{-3}}{2(1)}$
$\sqrt{-3} $ is not a real number, ($\Delta$ is negative)
so
there are no real solutions.
