Answer
no real solutions
Work Step by Step
Quadratic formula, a=$2$, b=$-4$, c=$3$
$x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$
Checking $\Delta=b^{2}-4ac=16-4(2)(3)=-8$
$\Delta$ is negative
so
there are no real solutions.
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