Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 9

Answer

Equation of parabola is $y^{2}=-x$ Focus: $(-\frac{1}{4},0)$ Directrix : $x=\frac{1}{4}$

Work Step by Step

$y^{2}=4px$ is the equation of the parabola with vertex $(0,0)$ focus $(p,0)$ and directrix $x=-p$ From the graph, we can see that $(-1,1)$ is a point on the curve. Thus, $(1)^{2}=4p(-1)$ Hence, $p=-\frac{1}{4}$ Equation of parabola is: $y^{2}=-x$ Focus: $(-\frac{1}{4},0)$ Directrix : $x=\frac{1}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.