Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 4

Answer

vertex: $(0,0)$ Focus: $(0,-\frac{2}{3})$ Directrix: $y=\frac{2}{3}$

Work Step by Step

$3x^2+8y=0$ or, $x^2=4(\frac{-2}{3})y$ Thus, vertex: $(0,0)$ Focus: $(0,-\frac{2}{3})$ Directrix: $y=\frac{2}{3}$
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