Answer
$\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$
Work Step by Step
Here, $a=3$ and $c=5$ from the given points
we can write
$5^2=3^2+b^2$
$25-9=b^2$
$b^2=16$
The equation of the hyperbola is:
$\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 43
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