Answer
Hyperbola
Foci: $( \pm \sqrt 5,0)$
Vertices: $(\pm1,0,)$
Work Step by Step
$4x^2=y^2+4$
$\frac{x^{2}}{1^2}-\frac{y^{2}}{2^2}=1$, the equation of a hyperbola.
$c^{2}=1+4=5$
$c=\sqrt 5$
Foci: $( \pm \sqrt 5,0)$
Vertices: $(\pm1,0,)$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 25
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