Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 33

Answer

$y^2=-12(x+1)$

Work Step by Step

Distance of the point $(x,y)$ from the line $x=2$ is $|x-2|$ Therefore, the equation of the parabola is $|x-2|=\sqrt {(x+4)^2+y^{2}}$ $y^2=-12x-12$ or $y^2=-12(x+1)$
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