Answer
$h(x)=\sqrt x$
$g(x)=x-1$
$f(x)=\sqrt x$
Work Step by Step
Separating the function into three processes:
$1. h(x)=\sqrt x$
$2.g(h(x))=g(\sqrt x)=\sqrt x-1=h(x)-1$
$g(x)=x-1$
$3.f(g(h(x)))=f(\sqrt x-1)=\sqrt {\sqrt x-1}=\sqrt {g(h(x))}$
$f(x)=\sqrt x$