Answer
$g(x)=\frac{x}{1+x}$
$f(x)=\sqrt[3] x$
Work Step by Step
Separating the function into two processes:
$1. g(x)=\frac{x}{1+x}$
$2. f(g(x))=f(\frac{x}{1+x})=\sqrt[3] \frac{x}{1+x}=\sqrt[3] (g(x))$
$f(x)=\sqrt[3] x$
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