Answer
$g(x)=\sqrt[3] x$
$f(x)=\frac{x}{1+x}$
Work Step by Step
Separating the function into two processes:
1. $g(x)=\sqrt[3] x$
2. $f(g(x))=f(\sqrt[3] x)=\frac{\sqrt[3] x}{1+\sqrt[3] x}=\frac{g(x)}{1+g(x)}$
$f(x)=\frac{x}{1+x}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises - Page 44: 45
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