Answer
$f(g(h(x)))=tan(\frac{\sqrt[3] x}{\sqrt[3] x-1})$
Work Step by Step
We need to find $f(g(h(x)))$. To do this we can first substitute g(x) into our f(x) equation. $f(g(x))=tan(\frac{x}{x-1})$. Next, we can further substitute in h(x) into our previous function to create $f(g(h(x)))=tan(\frac{\sqrt[3] x}{\sqrt[3] x-1})$ .
