Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.8 Implicit Differentiation - 3.8 Exercises - Page 200: 11

Answer

$(a)$ $$\frac{dy}{dx}=-\csc y$$ $(b)$ The slope of the tangent line to the curve is $m=-1$

Work Step by Step

$(a)$ Use implicit differentiation to determine $\frac{dy}{dx}$ for $\cos y=x$ Taking the derivative implicitly we get: $$-\sin y\frac{dy}{dx}=1$$ solve for $\frac{dy}{dx}$ $$\frac{dy}{dx}=\frac{1}{-\sin y}=-\csc y$$ $(b)$ Find the slope of the tangent line to the curve at $(0,\pi/2 )$ We plug in the point $(0,\pi/2 )$ into the derivative from part $(a)$. Hence: $$\frac{dy}{dx}=-\csc (\pi/2)=-1$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.