Answer
$g(x)$; $x$
The derivative of $f(g(x))$ equals $f'$ evaluated at $\boxed{g(x)}$ multiplied by $g'$ evaluated at $\boxed x$
Work Step by Step
According to Theorem 3.14:
$\frac{d}{dx}[f(g(x))]=f'(g(x)) \times g'(x)$
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